新GRE数学全部考点及解析(17).

　　新GRE数学考试要求的是中学的数学知识，考生们对于新GRE数学上面来说还是比较有把握，不过说到具体的GRE数学考点要求就不一定这么清楚。下面就为大家介绍新GRE数学考点及这些GRE数学考点解析，帮助考生们系统的复习一遍新GRE数学，梳理整合新GRE数学考试所需要的知识。

　　GRE考试数学考点：AP

　　Average of n numbers of arithmetic progression (AP) is the average of the smallest and the largest number of them. The average of m number can also be written as x + d(m-1)/2.

　　Example:

　　The average of all integers from 1 to 5 is (1+5)/2=3

　　The average of all odd numbers from 3 to 3135 is (3+3135)/2=1569

　　The average of all multiples of 7 from 14 to 126 is (14+126)/2=70

　　remember:

　　Make sure no number is missing in the middle.

　　With more numbers, average of an ascending AP increases.

　　With more numbers, average of a descending AP decreases.

　　AP:numbers from sum

　　given the sum s of m numbers of an AP with constant increment d, the numbers in the set can be calculated as follows:

　　the first number x = s/m - d(m-1)/2,and the n-th number is s/m + d(2n-m-1)/2.

　　Example:

　　if the sum of 7 consecutive even numbers is 70, then the first number x = 70/7 - 2(7-1)/2 = 10 - 6 = 4.　　the last number (n=m=7)is 70/7+2(2*7-7-1)/2=10+6=16.the set is the even numbers from 4 to 16.

　　Remember:

　　given the first number x, it is easy to calculate other numbers using the formula for n-th number: x+(n-1)

　　AP:numbers from average

　　all m numbers of an AP can be calculated from the average. the first number x = c-d(m-1)/2, and the n-th number is c+d(2n-m-1)/2, where c is the average of m numbers.

　　Example:

　　if the average of 15 consecutive integers is 20, then the first number x=20-1*(15-1)/2=20-7=13 and the last number (n=m=15) is 20+1*(2*15-15-1)/2=20+7=27.

　　if the average of 33 consecutive odd numbers is 67, then the first number x=67-2*(33-1)/2=67-32=35 and the last number (n=m=33) is 67+2*(2*33-33-1)/2=67+32=99.

　　Remember:

　　sum of the m numbers is c*m,where c is the average.

　　以上就是新GRE数学考点及GRE数学考点解析的介绍，希望这些知识点的介绍可以帮助大家复习新GRE数学，为大家复习新GRE数学提供条件。希望考生们认真复习新GRE数学考试，能够取得自己理想的成绩。澳际也会不断的为大家分享更多有助于考生们复习考试的新GRE考试材料及技巧。