悉尼大学商学国贸双硕士毕业,现居澳洲,在澳学习生活15+年,从事教育咨询工作超过10年,澳洲政府注册教育顾问,上千成功升学转学签证案例,定期受邀亲自走访澳洲各类学校
您所在的位置: 首页> 新闻列表> SAT2化学练习:Limiting Reagents.
今天澳际小编为大家整理了SAT2化学练习:Limiting Reagents,供大家参考,希望这些练习能够帮助大家更好地备考SAT2化学考试,以下是详细内容。
Have you ever noticed that hot dogs are sold in packages of 10, while the buns come in packages of eight? In this scenario, the buns are the limiting reactant in the sense that they limit the hot dog preparation to eight. The limiting reactant or reagent is the one that is consumed first in the chemical reaction, and its consumption halts the progress of the forward reaction. When answering questions about limiting reagents on the exam, your first step should always be to convert all the masses you were given into moles. You should set up your table as you did bore, only now you’ll have two amounts and thus two numbers of moles to get you started. Let’s look at a specific question, involving the Haber process. Basically, this is the process of making ammonia from the reaction of nitrogen and hydrogen gases. The reaction is shown below:Molar mass(28.02)(2.02)(17.04)
Balanced equation N2 +3H2 2NH3
No. of moles
Amount
Suppose you have a total of 25.0 kg of nitrogen to react with a total of 5.00 kg of hydrogen. What mass of ammonia can be produced? Which reactant is the limiting reactant? What is the mass of the reactant that’s in excess? Insert the masses in the correct rows and find the number of moles of both.
Molar mass(28.02)(2.02)(17.04)
Balanced equation N2 +3H2 2NH3
No. of moles892 mol2475 mol
Amount25,000 g5000 g
Start with nitrogen. You have 892 moles of it available, and in order for the nitrogen to react completely with hydrogen, you’d need 3(892 mol) = 2676 moles of hydrogen, which you don’t have. Therore, hydrogen is the limiting reagent. Now let’s answer the other parts of the question. The mass of ammonia that can be produced is limited by the amount of hydrogen, so do your calculations based on the number of moles of hydrogen available. Your chart should look like the one below:Molar mass(14.02)(2.02)(17.04)
Balanced equationN2 +3H2 2NH3
No. of moles825 mol used2475 mol usedtherore 1650 mol produced
Amount 892 mol 23,117 g used 25,000g 5000 g1650 mol (17.04) = 28,116 g produced
以上便是Limiting Reagents的SAT2化学练习介绍,希望对大家有所帮助。更多SAT考试相关资料尽在澳际教育网SAT考试频道,澳际小编祝大家都能取得理想的SAT2化学考试成绩!
Amy GUO 经验: 16年 案例:4272 擅长:美国,澳洲,亚洲,欧洲
本网站(www.aoji.cn,刊载的所有内容,访问者可将本网站提供的内容或服务用于个人学习、研究或欣赏,以及其他非商业性或非盈利性用途,但同时应遵守著作权法及其他相关法律规定,不得侵犯本网站及相关权利人的合法权利。除此以外,将本网站任何内容或服务用于其他用途时,须征得本网站及相关权利人的书面许可,并支付报酬。
本网站内容原作者如不愿意在本网站刊登内容,请及时通知本站,予以删除。